About

My name is Alex Barter I am 19 years old. I am very interested in cryptography and programming in general, I mostly program in the object orientated program Java. I first starting programming in about 2011 making modifications for the well known game pc Minecraft. After making a significant amount of money and my modifications being featuring on some of the biggest YouTube channels my attention was captured by the National Cipher Challenge.

My first was the 2013 Cipher Challenge in which I entered with a friend, we manged to do most the challenges apart from the last 2, overall coming about 200th. In 2014 we both entered again, again coming about 200th. In 2015 we had 2 more friends join our team, we came 2nd winning the IBM Prize of £800. This year (2016-17) I entered as a solo participant, hoping to do one better with my exhaustive list of cipher programs. I did succeed, gaining the Gold Award and the GCHQ Prize of £1000! Well done to everyone else who entered in the challenge. Harry compiled a guide created from the winners methods and processes when cracking 8B.

Cryptography-Team-2016

Most the content on this website will be aimed to help explain how many ciphers work and how to break them (find the key). The ciphers will range all the way from the Caesar Shift to the most famous: the Enigma Machine cipher and possibly some you have never seen before!

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4 thoughts on “About

  1. Joseph

    Hi Alex,

    I read your interesting article about how to decrypt a Hill cipher without the key.

    Would you help me to decrypt “FYKUTD FW BIBH TK NACP”
    (You can remove the space characters).
    It uses a 3×3 matrix.
    The result output should be French.

    It’s a challenge from a friend. And I would be happy to find the solution 🙂

    Cheers
    Joseph

    Reply
    1. Alex Barter Post author

      I had a go and had no luck. There is simply not enough ciphertext to decrypt it. The method I described in my article preferably needs texts around 200 characters – this is 18 characters. Another reason why this likely unsolvable, as there is very little ciphertext, there could be multiply keys that decrypt the ciphertext to valid plaintext, where the plaintext is french and it makes sense.

      Please do let me know if you have had any luck. Sorry for the late reply and not being of much assistance.

      Alex

      Reply
  2. Doug Glover

    Hey Alex,

    I’m hoping you can help me. I have a book that I know contains a form of an Atbash Cipher. I have the key, but I can’t figure it out how to make it work as it does not follow the traditional workings of an Atbash Cipher. The key looks like the following:
    5 1 1
    7 1 36
    11 6 164

    Thanking you in advance for any help you can give.
    Doug

    Reply
  3. Lawrence Barter

    Hey Alex,

    I’m having a struggle cracking the code to my neighbours safe with lots of money in it.

    Please help:

    P3N 15L4ND XD

    Thanks Alot!

    Reply

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